Protein Function: Enzymes

see Biology, 5th edition, by Campbell, Reece and Mitchell, Chapter 6.


What are enzymes?
Do enzymes have to be proteins?

What do they do? What is a catalyst?

What are the properties of enzymes as catalysts?

What is a substrate?

How do enzymes accelerate rates?

Where on the enzyme does the chemical transformation of the substrate occur?

What is the active site?

What is the function of the 3-D structure of a protein?

What determines substrate or ligand binding to a protein?


How do we measure enzyme catalyzed reactions?

What are the main features of enzyme kinetics?

For the reaction of a substrate, S, with an enzyme, E, leading to formation of a product, P:

How do drugs inhibit enzyme catalysed reactions?

There are three types of inhibition:

What is site-directed mutagenesis?


What are the six classes of enzymes?
Enzyme class is based on reaction type.
Enzyme names end in -ase usually as *reaction type*-ase. For example, hydrolysis = hydrolase

1. oxidation and reduction: oxidoreductases, commonly the addition or removal of H
2. transfer of a chemical group: transferases, eg kinases
3. hydrolysis: hydrolases
4. two reactions of opposite type, eliminations and additions
5. interconversion of isomers: isomerases
6. addition reactions requiring energy: synthetases

Enzyme kinetic calculation

The kinetics of an enzyme catalyzed reaction are determined in the presence and absence of an inhibitor at different substrate concentrations. You obtain the following data:
v (millimoles/min)
[S](millimoles)controlinhibitor
1.251.720.98
1.672.041.17
2.502.631.47
5.003.331.96
10.004.122.38
Estimate Vmax and Km in the presence and absence of the inhibitor.
What kind of inhibition is involved (competitive or non-competitive)?




Plot the data as v vs [S], velocity versus substrate concentration.

From the Michaelis-Menten plot (upper panel), inhibition is non-competitive, the decrease in Vmax even at high substrate concentrations being diagnostic for this type of inhibition. (Note: competitive inhibition is overcome by high substrate concentrations)



Numerical estimates of Vmax and Km are made from a linear plot, the double reciprocal or Lineweaver-Burk plot (lower panel).



The intercept on 1/v is 0.197 for the control (circles) so that Vmax = 5.1 mmole/min.
Note: you cannot get a good estimate of Vmax from the Michaelis-Menten plot.
For the control data the slope (Km/Vmax) is 0.481 and Km = 2.4 mM (Vmax x slope)

For the data with inhibitor, the intercept on 1/v is 0.337 and Vmax = 3.0 mmole/min.
The slope is 0.858 and Km = 2.5 mM
A decrease in Vmax with the same Km is diagnostic of non-competitive inhibition

From the intercept on 1/S axis, -1/Km is -0.4 and Km is 2.5 mM


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Bich 107 lecture notes on Enzymes were last updated 10/06/03

Comments to Martyn Gunn